Tentukan persamaan kuadrat yang akar-akarnya -⅖ dan 3
pakee cara yaaa
pakee cara yaaa
x₁ = -2/5
(x + 2/5) = 0
x₂ = 3
(x - 3) = 0
(x + 2/5)(x - 3) = 0
x² + (2/5)x - 3x - 6/5 = 0
x² + (2/5)x - (15/5)x - 6/5 = 0
x² - (13/5)x - 6/5 = 0
5x² - 13x - 6 = 0
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